Solution: Sqrt(x)
Explore how to calculate the floor of the square root of a non-negative integer using a modified binary search technique. Understand how to set search boundaries, adjust pointers based on comparisons, and achieve an efficient solution with O(log n) time complexity and O(1) space complexity without relying on built-in exponent functions.
We'll cover the following...
We'll cover the following...
Statement
Given a non-negative integer x, compute and return the square root of x rounded down to the nearest integer. The result must also be non-negative.
Built-in exponent functions or operators (e.g., pow(x, 0.5) in C++ or x ** 0.5 in Python) are not permitted.
Constraints:
x
Solution
The key insight is that the integer square root of x lies somewhere in the range