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Grokking the Coding Interview Patterns in Go

Solution: Minimum Remove to Make Valid Parentheses

Explore how to use a stack to remove unmatched parentheses from a string to ensure valid parenthesization. Understand the step-by-step process and analyze time and space complexity to implement this solution efficiently in Go.

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Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

  • 1≤1 \leq s.length
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