Solution: Minimum Remove to Make Valid Parentheses

Explore how to apply stack data structures to remove the fewest invalid parentheses from a string to produce a valid sequence. Understand the Last In, First Out (LIFO) method to track opening and closing parentheses and learn to implement an efficient solution that traverses the string once with O(n) time complexity.

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Statement
Solution
- Time complexity
- Space complexity

Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

$1 \leq$ s.length

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