Solution: Minimum Remove to Make Valid Parentheses

Understand how to use a stack to remove the fewest invalid parentheses from a string, ensuring a valid arrangement. Explore step-by-step techniques to traverse the string, track parentheses with indices, and efficiently modify the input for correct parenthesization.

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Statement
Solution
- Time complexity
- Space complexity

Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

$1 \leq$ s.length

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