Solution: Reorganize String
Explore how to rearrange a string to avoid adjacent identical characters by using character frequency mapping and max heap data structures. Understand how to build and manipulate heaps to ensure valid reorganizations, and learn when reorganization is impossible. This lesson helps you implement efficient solutions with clear time and space complexity insights.
Statement
Given a string, str, rearrange it so that any two adjacent characters are not the same. If such a reorganization of the characters is possible, output any possible valid arrangement. Otherwise, return an empty string.
Constraints:
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str.length - Input string consists of lowercase English letters.
Solution
So far, you’ve probably brainstormed some approaches and have an idea of how to solve this problem. Let’s explore some of these approaches and figure out which one to follow based on considerations such as time complexity and any implementation constraints.
Naive approach
The naive approach is to generate all possible permutations of the given string and check if the generated string is a valid arrangement or not. If any permutation satisfies the condition of a valid reorganization of the string, return that permutation of the input string. If no permutation is a valid reorganization of the string, return an empty string.
The number of possible permutations for a string of length ...