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Solution: Regular Expression Matching

Explore how to solve the regular expression matching problem by applying dynamic programming techniques. Understand how to use recursion with memoization to efficiently handle patterns containing '.' and '*' characters, ensuring optimal performance by avoiding redundant calculations.

Statement

You are given an input string, s, and a pattern string, p. Your task is to implement regular expression matching between s and p, where the pattern may include the special characters '.' and '*':

  • '.' matches any single character.

  • '*' matches zero or more occurrences of the preceding character.

The match must cover the entire input string, not just part of it.

Constraints:

  • 11 \leq s.length 20\leq 20

  • 11 \leq p.length 20\leq 20

  • s contains only lowercase English letters.

  • p contains only lowercase English letters, '.', and '*'.

  • It is guaranteed that for each appearance of the character '*', there will be a previous valid character to match.

Solution

One of the first ideas that comes to mind to solve the regular expression matching problem is to compare the string s and the pattern p character by character. At each step, we could check if the current characters match, and when we encounter special symbols like '.' or '*', we could try to handle them separately. However, this naive approach quickly becomes complicated because the '*' operator can represent zero or more repetitions of the previous character, leading ...