Solution: Rearrange Sorted List in Max/Min Form

Explore how to rearrange a sorted list so that elements alternate between the largest and smallest values. Learn two efficient approaches: creating a new list and using in-place encoding with modulus and two pointers. Understand the algorithm's steps, constraints, and complexity for coding interviews.

We'll cover the following...

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Solution 1: Create a new list
- Complexity analysis
Solution 2: Use modulus (%) and two pointers
- Complexity analysis

Statement

We're given a sorted list, nums, containing positive integers only. We have to rearrange the list so that when returned, the $0^{th}$ index of the list will have the largest number, the $1^{st}$ index will have the smallest number, the $2^{nd}$ index will have the second largest number, the $3^{rd}$ index will have the second smallest number, and so on.

In the end, we’ll have the largest remaining numbers in descending order and the smallest in ascending order at even and odd positions, respectively.

Constraints:

$0 \leq$ nums.length $\leq 10^3$ ...

1.Introduction

2.Algorithm Analysis for Interviews

3.Arrays

4.Linked Lists

5.Stacks

6.Queues

7.Heaps & Priority Queues

8.Hashing

9.Introduction to Trees

10.Introduction to Graphs

11.Trie

12.Interview Readiness and Strategy

Mock Interview

Solution: Rearrange Sorted List in Max/Min Form

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