Solution: Rearrange Sorted Array in Max/Min Form

Explore methods to rearrange a sorted array so that elements alternate between the largest and smallest remaining values. Learn two approaches: creating a new array and using a modulus-based in-place technique. Understand their time and space complexities to optimize array manipulation in C++ coding interviews.

We'll cover the following...

Statement
Solution 1: Create a new array
- Complexity analysis
Solution 2: Use modulus (%) and two pointers
- Complexity analysis

Statement

We're given a sorted array, nums, containing positive integers only. We have to rearrange the array so that when returned, the $0^{th}$ index of the array will have the largest number, the $1^{st}$ index will have the smallest number, the $2^{nd}$ index will have the second largest number, the $3^{rd}$ index will have the second smallest number, and so on.

In the end, we’ll have the largest remaining numbers in descending order and the smallest in ascending order at even and odd positions, respectively.

Constraints:

$0 \leq$ nums.length $\leq 10^3$ ...

1.Introduction

2.Algorithm Analysis for Interviews

3.Arrays

4.Linked Lists

5.Stacks

6.Queues

7.Heaps & Priority Queues

8.Hashing

9.Trees

10.Graphs

11.Trie

12.Interview Readiness and Strategy

Mock Interview

Solution: Rearrange Sorted Array in Max/Min Form

Statement