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Learn Data Structures and Algorithms in C++

Problem: Valid Palindrome

Explore how to verify if a string is a valid palindrome by using two pointers to compare characters while ignoring case and non-alphanumeric symbols. Learn to implement this efficient string algorithm with O(n) time and O(1) space complexity, enhancing your C++ problem-solving skills.

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Statement

A phrase is considered a palindrome if, after converting all uppercase letters to lowercase and stripping all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include both letters and numbers.

Given a string s, return TRUE if it qualifies as a palindrome after the transformations described above, or FALSE otherwise.

Note: An empty string (which may result after removing all non-alphanumeric characters) is considered a palindrome.

Constraints:

  • 1≤1 \leq s.length ≤2×105\leq 2 \times 10^5 ...