Linked List Cycle II
Try to solve the Linked List Cycle II problem.
We'll cover the following
Statement
Given the head of a linked list, return the node where the cycle begins. If there is no cycle, return nullptr
. A cycle exists in a linked list if there is some node in the list that can be reached again by continuously following the next
pointer.
Constraints:
- Number of the nodes in the list
-
Node.val
Examples
Level up your interview prep. Join Educative to access 80+ hands-on prep courses.