Solution: Word Break
Explore how to apply dynamic programming to solve the Word Break problem in C++. This lesson guides you through building a lookup table to check string segmentation against a dictionary, improving efficiency by avoiding redundant checks. By the end, you'll understand the algorithm's time and space complexity and be able to implement this common interview pattern effectively.
Statement
Given a string, s, and a dictionary of strings, wordDict, check if s can be segmented into a space-separated sequence of one or more dictionary words. If yes, return TRUE; else, return FALSE.
Note: The same word in the dictionary may be used multiple times.
Constraints:
-
s.length -
wordDict.length...