Split a Circular Linked List
Explore how to divide a circular linked list into two equal parts by applying fast and slow pointer methods. This lesson helps you understand linked list structure, manage nodes efficiently, and implement the split with correct order preservation in C++.
We'll cover the following...
Statement
Given a circular linked list, list, of positive integers, split it into two circular linked lists. The first circular linked list should contain the first half of the nodes (exactly ⌈list.length / 2⌉ nodes) in the same order they appeared in the original list, while the second circular linked list should include the remaining nodes in the same order.
Return an array, answer, of length 2, where:
answer[0]is the head of the circular linked list representing the first half.answer[1]is the head of the circular linked list representing the second half.
Note: A circular linked list is a standard linked list where the last node points back to the first node.
Constraints:
Let n be the number of nodes in a linked list.
2
...